August 2004
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This illustrates two speakers wired in parallel. Wired thus, the circuit load is equal to the speaker ohm divided by the number of drivers in the circuit. In this case, 8 (ohm speaker) divided by 2 (speakers) = 4 ohm load. |
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This is the same as the previous diagram but with 16-ohm drivers. 16 (ohm speaker) divided by 2 (speakers) = 8 ohm load. |
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Here we have four drivers wired in parallel. This very config can be found plugged into older Fender amps. In
this example, our resulting load is 4 ohms. We could do the same with 8 or even 4 ohm drivers, but what would you be plugging a 2-ohm or 1-ohm cabinet into? |
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Here we have two drivers wired in series. Wired thus, the circuit load is equal to the speaker ohm multiplied by the number of drivers in the circuit. In this case, 4 (ohm speaker) multiplied by 2 (speakers) = 8 ohm load. |
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This is identical to the previous diagram, but with 8-ohm drivers. 8 (ohm speaker) multiplied by 2 (speakers) = 16 ohm load. |
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In this example, picture the speakers on the left as a single two speaker circuit that is wired in parallel thus:
4 (ohm speaker) divided by 2 (speakers) = 2 ohm load. This single 2-ohm load has a pos and neg connection. |
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This diagram is the same as the previous, but with 8-ohm drivers. As above, consider each set of speakers (left;
right) as their own parallel circuit, which are then connected in series. |
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The final parallel/series diagram. Same as previous two, but with 16-ohm drivers. |
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In this first diagram, the speakers on the left are wired in series as a single two-speaker circuit thus: 4 (ohm
speaker) multiplied by 2 (speakers) = 8 ohm load. |
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Same diagram but with 8-ohm drivers. The formula is the same. |
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And finally, the same series/parallel circuit with 16-ohm drivers. |
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